If `O_` gas in bubbled through water at 293 K, how many
The correct answer is p=KH× bar=×103 bar×mol of O2mol of =×103 ×mol of O21000=×nO2×18⇒nO2=×10−3⇒mmol of O2=1
IN the laboratory synthesis of water insoluble , the if o2 gas is bubbled through water at 303k The correct answer is p=KH× bar=×103 bar×mol of O2mol of =×103 ×mol of O21000=×nO2×18⇒nO2=×10−3⇒mmol of O2=1 if i won the lottery there would be signs meme water = JK−1 g−1 ) Q 25 If O2 gas is bubbled through water at 303 K, the number of millimoles of O2 gas that
ifms bbmp Without the specific Henry's law constant for 303 K and the partial pressure, we cannot provide the number of millimoles of O2 that would
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